2024-01-18
∫(1/sint)dt=∫[sint/(sint)^2]dt=-∫{1/[1-cost)(1+cost)]}d(cost)=-(1/2)∫[1/(1-cost)+1/(1+cost)]d(cost)=-(1/2)∫[1/(1-cost)]d(cost)-(1/2)∫[1/(1+cost)]d(cost)=(1/2)ln(1-cost)-(1/2)ln(1+cost)+C=(1/2)ln[(1-cost)/(1+cost)]+C=(1/2)ln[(1-cost)^2/(sint)^2]+C=ln|1/sint-cott|+C。这个函数是不可积的,但是它...